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check if the number is Palindrome or not

August 13, 2022

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Algorithms

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Bayesian stone paper scissor

'''priority of computer is to draw or win the match''' import time import random import mysql.connector as c con=c.connect(host='localhost',user='root',password='',database='Machine_learning') if con.is_connected(): print('successfully connected') else: print('not connected') curso=con.cursor() sql="Select * from oldgames" curso.execute(sql) data=curso.fetchall() human_score,computer_score=0,0 rul_buk={'/':1,'*':2,'-':3} round=0; stone_pap=['/','*','-'] event2={'/':1.0,'*':1.0,'-':1.0} event={'/':data[0][1],'*':data[1][1],'-':data[2][1]} decision={'/':0.0,'*':0.0,'-':0.0} event_weight=0; weights2={'/':0.333,'*':0.333,'-':0.333}; weights={'/':data[0][2],'*':data[1][2],'-':data[2][2]}; def decs(): denominator=weights['/']*...

palindrome parser algorithm

If no. of Binary digits is greater than the number itself

import java . util . Scanner ; public class Check { public static void main ( String args []){ Scanner sc = new Scanner ( System .in); System .out. print ( "Enter the Number: " ); int n = sc. nextInt (); for ( int i = 2 ; i <= n;i ++ ){ String bin = load_binary (i); if (n == bin. length ()){ System .out. println (bin); } } } public static String load_binary ( int i ){ int n = i ; int bin = 0 ; while (n > 0 ){ bin = (bin * 10 ) + n % 2 ; n /= 2 ; } String bin2 = Integer . toString (bin); return bin2; } }

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check if the number is Palindrome or not

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